I am attempting to build out an IF statement that contains a long index/match formula in it. I want the IF statement to return the initial value that the index/match statement finds if the logical test is true. Is there a way to go about that without copying and pasting the formula?
=IF(
INDEX(
'2019'!$E$5:$BU$133,
MATCH(
Sheet1!$C$2&Sheet1!$C$3&$D8,
INDEX(
'2019'!$B$5:$B$133&'2019'!$C$5:$C$133&'2019'!$D$5:$D$133,
0
),
0
),
MATCH( Sheet1!E$7,'2019'!$E$3:$BU$3,0 )
) > '2019'!E6,
value_if_true,
value_if_false
)
So, if the index/match > 2019!E6
, i want to return the index/match value. Thanks for the help!