I adapted code I found online.
- It finds the string "car" in column A and returns the rows as an array
- It assigns a variable to the length of the array (how many matches it found)
- It assigns a variable to generate a random number between 0 and the length of the array
- It then prints a random matching row's value into K3
Dim myArray() As Variant
Dim x As Long, y As Long
Dim msg As String
With ActiveSheet.Range("A1:A"& ActiveSheet.Range("A"& Rows.Count).End(xlUp).Row)
Set c = .find("Car", LookIn:=xlValues)
If Not c Is Nothing Then
firstAddress = c.Address
Do
ReDim Preserve myArray(y)
myArray(y) = c.Row
y = y + 1
Set c = .findNext(c)
If c Is Nothing Then
GoTo DoneFinding
End If
Loop While c.Address <> firstAddress
End If
DoneFinding:
End With
For x = LBound(myArray) To UBound(myArray)
msg = msg & myArray(x) & ""
Next x
ArrayLen = UBound(myArray) - LBound(myArray)
random_index = WorksheetFunction.RandBetween(0, ArrayLen)
MsgBox myArray(random_index)
Dim test As String
test = "B"& myArray(random_index)
Range("K3").Value = Range(test)
Example
I'm struggling with adapting the find code to allow for multiple criteria. So in my example, it finds "Car". What if I want to find matches that had "Car" in column A and "Red" in column D?
I tried
With ActiveSheet.Range("A1:A"& "D1:D"& ActiveSheet.Range("A"& Rows.Count).End(xlUp).Row & ActiveSheet.Range("D"& Rows.Count).End(xlUp).Row)
Set c = .find("Car", "Red", LookIn:=xlValues)
I get type mismatch on the Set line.
In case it is confusing, it currently looks for a string e.g. "Car" but I will eventually link this to the variable which will be assigned to a data validation list. So if the user chooses "car" from a drop down list, this is what it will search for.